Which one of the following is the correct dec | vedclass

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(D) Among the hydrides of group $16$ elements,the boiling point of $H_2O$ is the highest due to strong intermolecular hydrogen bonding.For the remaini

Vedclass · Accepted Answer

$H_2O > H_2Te > H_2Se > H_2S$

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(D) Among the hydrides of group $16$ elements,the boiling point of $H_2O$ is the highest due to strong intermolecular hydrogen bonding.For the remaining hydrides ($H_2S$,$H_2Se$,$H_2Te$),the boiling point increases with the increase in molecular mass and size,which leads to stronger van der Waals forces.Thus,the order is $H_2O > H_2Te > H_2Se > H_2S$.

Which one of the following is the correct decreasing order of boiling point?

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