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(C) The correct decreasing order of boiling point is $H_2O > H_2Te > H_2Se > H_2S$.$H_2O$ has the highest boiling point due to strong intermolecular h

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$H_2O > H_2Te > H_2Se > H_2S$

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(C) The correct decreasing order of boiling point is $H_2O > H_2Te > H_2Se > H_2S$.$H_2O$ has the highest boiling point due to strong intermolecular hydrogen bonding.For the remaining hydrides $(H_2S, H_2Se, H_2Te)$,the boiling point increases with increasing molecular mass due to the increase in van der Waals forces of attraction.

Which one of the following is the correct decreasing order of boiling point?

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