Which one of the following is the most basic | vedclass

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(D) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom for protonation. In aromatic amines,the lone

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$C_6H_5-N(C_2H_5)_2$

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(D) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom for protonation. In aromatic amines,the lone pair is involved in resonance with the benzene ring,which decreases its availability. However,the presence of electron-donating groups (like alkyl groups) on the nitrogen atom increases the electron density on the nitrogen,thereby increasing its basicity. Comparing the given options: $C_6H_5-NH_2$ (Aniline) has no alkyl groups. $C_6H_5-NHCH_3$ has one methyl group. $C_6H_5-N(CH_3)_2$ has two methyl groups. $C_6H_5-N(C_2H_5)_2$ has two ethyl groups. Ethyl groups are better electron-donating groups than methyl groups due to the $+I$ effect. Therefore,$C_6H_5-N(C_2H_5)_2$ is the most basic compound among the given options.

Which one of the following is the most basic compound?

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