Which one of the following is wrongly matched?

  • A
    Saponification of $CH_3COOC_2H_5$ $-$ Second order reaction
  • B
    Hydrolysis of $CH_3COOCH_3$ $-$ Pseudo uni-molecular reaction
  • C
    Decomposition of $H_2O_2$ $-$ First order reaction
  • D
    Combination of $H_2$ and $Br_2$ to give $HBr$ $-$ Zero order reaction

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When the concentration of a reactant,$A$,in a reaction $A \to \text{Products}$ is doubled,the rate of reaction increases seven times. The order of the reaction is between:

For the reaction $NH_4^+ + NO_2^- \to N_2 + 2H_2O$,the experimental data is given below. Determine the rate law for the reaction.
$1.$ $[NH_4^+] = 0.24 \, M, [NO_2^-] = 0.10 \, M, \text{Rate} = 7.2 \times 10^{-6} \, M/s$
$2.$ $[NH_4^+] = 0.12 \, M, [NO_2^-] = 0.10 \, M, \text{Rate} = 3.6 \times 10^{-6} \, M/s$
$3.$ $[NH_4^+] = 0.12 \, M, [NO_2^-] = 0.15 \, M, \text{Rate} = 5.4 \times 10^{-6} \, M/s$

For the reaction between $A$ and $B$,the initial rate of reaction $(r_0)$ was measured for different initial concentrations of $A$ and $B$ as given below. Determine the order of the reaction with respect to $A$ and $B$ respectively.
$[A] / mol \ L^{-1}$$0.2, 0.2, 0.4$
$[B] / mol \ L^{-1}$$0.3, 0.1, 0.05$
$r_0 / mol \ L^{-1} s^{-1}$$5.0 \times 10^{-5}, 5.0 \times 10^{-5}, 1.4 \times 10^{-4}$

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For the reaction $2 N_2O_{5(g)} \longrightarrow 4 NO_{2(g)} + O_{2(g)}$,the rate and rate constant are $1.02 \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$ and $3.4 \times 10^{-5} \ s^{-1}$ respectively. What is the concentration of $N_2O_5$?

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