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(C) The carbylamine reaction is a characteristic test for primary $(1^o)$ amines,both aliphatic and aromatic.In this reaction,a primary amine reacts w

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$C_6H_5-NH-R$

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(C) The carbylamine reaction is a characteristic test for primary $(1^o)$ amines,both aliphatic and aromatic.In this reaction,a primary amine reacts with chloroform $(CHCl_3)$ and an alcoholic base $(KOH)$ to form an isocyanide (carbylamine),which has a foul smell.Secondary $(2^o)$ and tertiary $(3^o)$ amines do not contain the $-NH_2$ group required for this reaction.Analyzing the options:$(A)$ $H_2C=CH-CH_2-NH_2$ is a $1^o$ amine.$(B)$ $C_6H_5-NH_2$ (Aniline) is a $1^o$ amine.$(C)$ $C_6H_5-NH-R$ is a $2^o$ amine.$(D)$ Cyclohexylamine is a $1^o$ amine.Therefore,option $(C)$ will not give the carbylamine reaction.

Which one of the following will $NOT$ give the carbylamine reaction?

Similar Questions

$A$ positive carbylamine test is given by :-
$(a)$ $N,N$-Dimethylaniline
$(b)$ $2,4$-Dimethylaniline
$(c)$ $N$-methyl-$o$-methylaniline
$(d)$ $p$-Methylbenzylamine

Identify the Hinsberg reagent from the following.

Give one chemical test to distinguish between the following pairs of compounds:
$(i)$ Methylamine and dimethylamine
$(ii)$ Secondary and tertiary amines
$(iii)$ Ethylamine and aniline
$(iv)$ Aniline and benzylamine
$(v)$ Aniline and $N$-methylaniline.

Which of the following can be used to distinguish primary,secondary and tertiary amines?

Explain the isocyanide test.

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