Which one of the following will not show geom | vedclass

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(B) For a molecule to exhibit geometrical isomerism,each carbon atom of the $C=C$ double bond must be attached to two different groups. In option $B$,

Vedclass · Accepted Answer

$H_3C-C(CH_3)=C(Cl)Br$

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(B) For a molecule to exhibit geometrical isomerism,each carbon atom of the $C=C$ double bond must be attached to two different groups. In option $B$,the structure is $H_3C-C(CH_3)=C(Cl)Br$. The first carbon atom is attached to two identical methyl $(-CH_3)$ groups. Since the groups attached to the same carbon atom are not different,this molecule cannot show geometrical isomerism.

Which one of the following will not show geometrical isomerism?

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