Which of the following solubility orders is c | vedclass

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(D) The solubility of alkaline earth metal sulfates $(MSO_4)$ decreases down the group because the hydration enthalpy decreases more rapidly than the

Vedclass · Accepted Answer

$KOH > NaOH > LiOH$

Vedclass · Answer

(D) The solubility of alkaline earth metal sulfates $(MSO_4)$ decreases down the group because the hydration enthalpy decreases more rapidly than the lattice enthalpy as the size of the cation increases. Thus,the correct order is $MgSO_4 > CaSO_4 > SrSO_4 > BaSO_4$. For alkali metal hydroxides $(MOH)$,the solubility increases down the group due to the decrease in lattice energy being more significant than the decrease in hydration energy. Thus,the correct order is $LiOH Comparing the given options: Option $A$ is incorrect (it is the reverse of the actual trend). Option $B$ is incorrect (solubility of sulfides varies based on $K_{sp}$ values). Option $C$ is incorrect (solubility of carbonates increases down the group,but $Na_2CO_3$ is highly soluble). Option $D$ is correct: $KOH > NaOH > LiOH$.

Which of the following solubility orders is correct?

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