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(A) For an ideal mixture,the partial pressure of a component $i$ in the vapour phase is given by $P_i = P_i^o X_i$.Given the molar ratio is $1:1$,the

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The vapour will contain higher percentage of benzene

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(A) For an ideal mixture,the partial pressure of a component $i$ in the vapour phase is given by $P_i = P_i^o X_i$.Given the molar ratio is $1:1$,the mole fractions are $X_{benzene} = 0.5$ and $X_{toluene} = 0.5$.The partial pressures are $P_{benzene} = 75 	imes 0.5 = 37.5 \, mm \, Hg$ and $P_{toluene} = 22 	imes 0.5 = 11 \, mm \, Hg$.The mole fraction in the vapour phase is $Y_i = P_i / P_{total}$.Since $P_{benzene} > P_{toluene}$,it follows that $Y_{benzene} > Y_{toluene}$.Therefore,the vapour will contain a higher percentage of benzene.

Which statement about the composition of vapour over an ideal $1:1$ molar mixture of benzene and toluene is correct? Assume the temperature is constant at $25\,^{\circ}C$. Vapour pressure data $(25\,^{\circ}C)$:
Benzene: $75\, mm\, Hg$
Toluene: $22\, mm\, Hg$

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Which statement about the composition of vapour over an ideal $1:1$ molar mixture of benzene and toluene is correct? Assume the temperature is constant at $25\,^{\circ}C$. Vapour pressure data $(25\,^{\circ}C)$:Benzene: $75\, mm\, Hg$Toluene: $22\, mm\, Hg$