Which statement is correct?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. The $m.p.$ of $H_2O$ and $NH_3$ are indeed the highest in their respective groups ($Group$ $16$ and $Group$ $15$) due to the presence of stro

Vedclass · Accepted Answer

All are correct.

Vedclass · Answer

(D) $1$. The $m.p.$ of $H_2O$ and $NH_3$ are indeed the highest in their respective groups ($Group$ $16$ and $Group$ $15$) due to the presence of strong intermolecular $H$-bonding.$2$. The $b.p.$ of hydrides of $Group$ $14$ $(CH_4, SiH_4, GeH_4, SnH_4)$ increases with increasing molecular mass due to stronger van der Waals forces. Thus,$CH_4$ has the lowest $b.p.$$3$. Formic acid $(HCOOH)$ exists as a dimer in the vapor state and in non-polar solvents due to intermolecular $H$-bonding.$4$. Since all statements are correct,the correct option is $D$.

Similar Questions

Intramolecular $H$-bond is present in

The boiling points of methanol,water,and dimethyl ether are respectively $65\,^{\circ}C$,$100\,^{\circ}C$,and $-24.8\,^{\circ}C$ (note: dimethyl ether is a gas at room temperature). Which of the following best explains these wide variations in boiling point $(b.p.)$?

Which of the following hydrogen bonds is the strongest in the vapour phase?

Assertion : Molar enthalpy of vaporisation of water is different from ethanol.
Reason : Water is more polar than ethanol.

The boiling points at atmospheric pressure of $HF$,$H_2S$,and $NH_3$ can be arranged in the following order:

Vedclass Test Series

Exam Paper Generator

Online Exam Module