Which statement is not true regarding the 2s | vedclass

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(D) For an $ns$ orbital,the number of radial nodes is given by the formula $(n - l - 1)$.For $2s$ orbital,$n = 2$ and $l = 0$,so radial nodes $= 2 - 0

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Probability density is zero at the nucleus

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(D) For an $ns$ orbital,the number of radial nodes is given by the formula $(n - l - 1)$.For $2s$ orbital,$n = 2$ and $l = 0$,so radial nodes $= 2 - 0 - 1 = 1$,which is greater than zero. Thus,option $A$ is true.For any $s$ orbital,the angular momentum quantum number $l = 0$,so the number of angular nodes is $l = 0$. Thus,option $B$ is true.The wave function $\Psi$ for an $s$ orbital is spherically symmetric,meaning it depends only on the radial distance $r$ and is independent of the angular coordinates $	heta$ and $\phi$. Therefore,$\Psi \left( 	heta, \phi ight) = 	ext{constant}$ is true.The probability density is given by $|\Psi|^2$. For $s$ orbitals,the electron density is maximum at the nucleus $(r = 0)$. Therefore,the statement that probability density is zero at the nucleus is false.

Which statement is not true regarding the $2s$ orbital?

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