Which term of the A.P. -1, 3, 7, 11, ldots is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given $A.P.$ is $-1, 3, 7, 11, \ldots$Here,the first term $a = -1$.The common difference $d = 3 - (-1) = 3 + 1 = 4$.Let the $n^{th}$ term be $a_n

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(B) Given $A.P.$ is $-1, 3, 7, 11, \ldots$Here,the first term $a = -1$.The common difference $d = 3 - (-1) = 3 + 1 = 4$.Let the $n^{th}$ term be $a_n = 95$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.Substituting the values: $95 = -1 + (n - 1)4$.$95 + 1 = (n - 1)4$.$96 = (n - 1)4$.$n - 1 = 96 / 4 = 24$.$n = 24 + 1 = 25$.Therefore,the $25^{th}$ term of the $A.P.$ is $95$.

Which term of the $A.P.$ $-1, 3, 7, 11, \ldots$ is $95$ (in $^{th}$)?

Similar Questions

Which term of the $A.P.$ $5, 10, 15, \ldots$ exceeds its $31^{st}$ term by $130$ (in $^{th}$)?

Find the $100^{th}$ term of the $A.P.$ $50, 56, 62, 68, \ldots$

In an $A.P.$,ten times the $10^{th}$ term equals fifteen times the $15^{th}$ term. Prove that the $25^{th}$ term of the $A.P.$ is $0$.

For each of the following $A.P.s$,find the $n^{th}$ term: $10.5, 11.7, 12.9, 14.1, \dots$

For any $A.P.$,$T_{25} - T_{20} = \ldots \ldots \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module