Which term of the A.P. 3, 8, 13, ldots is 248 | vedclass

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Question

(A) Given $A.P.$ is $3, 8, 13, \ldots, 248$.Here,the first term $a = 3$ and the common difference $d = 8 - 3 = 5$.Let the $n^{th}$ term be $a_n = 248$

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(A) Given $A.P.$ is $3, 8, 13, \ldots, 248$.Here,the first term $a = 3$ and the common difference $d = 8 - 3 = 5$.Let the $n^{th}$ term be $a_n = 248$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.Substituting the values: $248 = 3 + (n - 1)5$.$248 - 3 = (n - 1)5$.$245 = (n - 1)5$.$n - 1 = 245 / 5 = 49$.$n = 49 + 1 = 50$.Therefore,the $50^{th}$ term of the $A.P.$ is $248$.

Which term of the $A.P.$ $3, 8, 13, \ldots$ is $248$ (in $^{th}$)?

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