Which would decrease the pH of 25 cm^3 of a | vedclass

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(B) The $pH$ of a solution is defined as $pH = -\log[H^+]$.To decrease the $pH$,the concentration of $H^+$ ions must increase.Option $A$: Adding $25 \

Vedclass · Accepted Answer

The addition of $25 \ cm^3$ of $0.02 \ M$ hydrochloric acid

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(B) The $pH$ of a solution is defined as $pH = -\log[H^+]$.To decrease the $pH$,the concentration of $H^+$ ions must increase.Option $A$: Adding $25 \ cm^3$ of $0.005 \ M$ $HCl$ to $25 \ cm^3$ of $0.01 \ M$ $HCl$ results in a final concentration of $[H^+] = \frac{(25 	imes 0.01) + (25 	imes 0.005)}{50} = 0.0075 \ M$,which is lower than $0.01 \ M$,so $pH$ increases.Option $B$: Adding $25 \ cm^3$ of $0.02 \ M$ $HCl$ to $25 \ cm^3$ of $0.01 \ M$ $HCl$ results in a final concentration of $[H^+] = \frac{(25 	imes 0.01) + (25 	imes 0.02)}{50} = 0.015 \ M$,which is higher than $0.01 \ M$,so $pH$ decreases.Option $C$: Adding magnesium metal consumes $H^+$ ions $(Mg + 2H^+ ightarrow Mg^{2+} + H_2)$,which decreases $[H^+]$ and increases $pH$.

Which would decrease the $pH$ of $25 \ cm^3$ of a $0.01 \ M$ solution of hydrochloric acid?

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