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(B) The kinetic energy $(KE)$ of an object is given by the formula: $KE = \frac{1}{2}mv^2$.$1$. If we double the mass $(m' = 2m)$,the new kinetic ener

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Doubling the velocity

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(B) The kinetic energy $(KE)$ of an object is given by the formula: $KE = \frac{1}{2}mv^2$.$1$. If we double the mass $(m' = 2m)$,the new kinetic energy becomes: $KE' = \frac{1}{2}(2m)v^2 = 2 	imes KE$. Thus,doubling the mass doubles the kinetic energy.$2$. If we double the velocity $(v' = 2v)$,the new kinetic energy becomes: $KE'' = \frac{1}{2}m(2v)^2 = \frac{1}{2}m(4v^2) = 4 	imes KE$. Thus,doubling the velocity increases the kinetic energy by four times.Since $4 	imes KE > 2 	imes KE$,doubling the velocity has a greater effect on the kinetic energy of an object.

Which would have a greater effect on the kinetic energy of an object: doubling the mass,or doubling the velocity?

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