While a collector to emitter voltage is const | vedclass

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(A) Given: $\Delta I_c = 8.2 ~mA$ and $\Delta I_e = 8.3 ~mA$.We know that the emitter current is the sum of collector current and base current: $\Delt

Vedclass · Accepted Answer

$82$

Vedclass · Answer

(A) Given: $\Delta I_c = 8.2 ~mA$ and $\Delta I_e = 8.3 ~mA$.We know that the emitter current is the sum of collector current and base current: $\Delta I_e = \Delta I_c + \Delta I_b$.Therefore,the change in base current is $\Delta I_b = \Delta I_e - \Delta I_c = 8.3 ~mA - 8.2 ~mA = 0.1 ~mA$.The forward current gain (or current amplification factor $\beta$) is defined as the ratio of change in collector current to the change in base current:$\beta = \frac{\Delta I_c}{\Delta I_b} = \frac{8.2 ~mA}{0.1 ~mA} = 82$.

While a collector to emitter voltage is constant in a transistor,the collector current changes by $8.2 ~mA$ when the emitter current changes by $8.3 ~mA$. The value of forward current ratio is

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