While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made the following measurements:
$(i)$ Mass of water in the beaker $= 40 \text{ g}$.
(ii) Mass of raisins before soaking $= 5 \text{ g}$.
(iii) Mass of raisins after soaking for $2 \text{ hours} = 8 \text{ g}$.
(iv) Mass of water left in the beaker after the experiment $= 35 \text{ g}$.
The percentage of water absorbed by raisins is:

• A
  $\frac{40 \text{ g} - 35 \text{ g}}{35 \text{ g}} \times 100$
• B
  $\frac{40 \text{ g} - 35 \text{ g}}{40 \text{ g}} \times 100$
• C
  $\frac{8 \text{ g} - 5 \text{ g}}{8 \text{ g}} \times 100$
• D
  $\frac{8 \text{ g} - 5 \text{ g}}{5 \text{ g}} \times 100$