While working on a physics project at a schoo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To withstand a potential difference of $1000 \,V$ using capacitors that can only withstand $400 \,V$,we need to connect at least $n$ capacitors in

Vedclass · Accepted Answer

$18$

Vedclass · Answer

(B) To withstand a potential difference of $1000 \,V$ using capacitors that can only withstand $400 \,V$,we need to connect at least $n$ capacitors in series such that $n 	imes 400 \,V \geq 1000 \,V$. Thus,$n \geq 2.5$,so we must use at least $n = 3$ capacitors in series. The equivalent capacitance of $3$ capacitors of $2 \,\mu F$ each in series is $C_s = \frac{2 \,\mu F}{3}$. We need an equivalent capacitance of $4 \,\mu F$. Let $m$ be the number of such series branches connected in parallel. Then,$m 	imes C_s = 4 \,\mu F \Rightarrow m 	imes \frac{2}{3} \,\mu F = 4 \,\mu F \Rightarrow m = \frac{4 	imes 3}{2} = 6$. Total number of capacitors = (number of branches in parallel) $	imes$ (number of capacitors in series) = $6 	imes 3 = 18$.

Similar Questions

$STATEMENT-1$: For practical purposes,the Earth is used as a reference at zero potential in electrical circuits.
$STATEMENT-2$: The electrical potential of a sphere of radius $R$ with charge $Q$ uniformly distributed on the surface is given by $\frac{Q}{4 \pi \varepsilon_0 R}$.

Three large plates are arranged as shown. How much charge will flow through the key $K$ if it is closed?

In the circuit shown in the figure,$K$ is open. The charge on capacitor $C$ in the steady state is $q_1$. Now,the key $K$ is closed,and at the steady state,the charge on $C$ is $q_2$. The ratio of charges $\left( \frac{q_1}{q_2} \right)$ is:

Three identical charged capacitors each of capacitance $5 \,\mu F$ are connected as shown in the figure. The potential difference across capacitor $(3)$,a long time after the switches $K_1$ and $K_2$ are closed,is ............ $V$.

Find the potentials at points $A$ and $B$ in the circuit shown in the figure.

Vedclass Test Series

Exam Paper Generator

Online Exam Module