White phosphorus is heated with concentrated | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When white phosphorus $(P_4)$ is heated with concentrated $NaOH$ in an inert atmosphere of $CO_2$,it undergoes disproportionation to form phosphin

Vedclass · Accepted Answer

$NaH_2PO_2, H_2SO_4$

Vedclass · Answer

(B) When white phosphorus $(P_4)$ is heated with concentrated $NaOH$ in an inert atmosphere of $CO_2$,it undergoes disproportionation to form phosphine $(PH_3)$ and sodium hypophosphite $(NaH_2PO_2)$.$P_4 + 3NaOH + 3H_2O \rightarrow PH_3(A) + 3NaH_2PO_2(B)$When phosphine $(A)$ is bubbled into aqueous $CuSO_4$ solution,it forms copper phosphide $(Cu_3P_2)$ and sulfuric acid $(H_2SO_4)$.$3CuSO_4 + 2PH_3 \rightarrow Cu_3P_2 + 3H_2SO_4(C)$Therefore,$B$ is $NaH_2PO_2$ and $C$ is $H_2SO_4$.

White phosphorus is heated with concentrated $NaOH$ in $CO_2$ atmosphere to form a gas $A$ and compound $B$. When $A$ is bubbled into aqueous $CuSO_4$ solution,copper phosphide and $C$ are formed. $B$ and $C$ are respectively:

Similar Questions

The basic character of hydrides of the $V$-group elements decreases in the order:

Haber process is used for the production of which of the following?

Which pair of metals does not dissolve in nitric acid?

Nitrogen dioxide $(NO_2)$ reacts with water to give:

Explain why $NH_3$ is basic while $BiH_3$ is only feebly basic.

Vedclass Test Series

Exam Paper Generator

Online Exam Module