White phosphorus reacts with sulphuryl chlori | vedclass

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Question

(A) White phosphorus $(P_4)$ reacts with sulphuryl chloride $(SO_2Cl_2)$ to form phosphorus pentachloride $(PCl_5)$ and sulphur dioxide ($SO_2$,which

Vedclass · Accepted Answer

$SO_2, SO_2Cl_2$

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(A) White phosphorus $(P_4)$ reacts with sulphuryl chloride $(SO_2Cl_2)$ to form phosphorus pentachloride $(PCl_5)$ and sulphur dioxide ($SO_2$,which is $X$).$P_4 + 10 SO_2Cl_2 \longrightarrow 4 PCl_5 + 10 SO_2$ $(X)$Chlorine $(Cl_2)$ reacts with sulphur dioxide ($SO_2$,$X$) in the presence of wood charcoal to form sulphuryl chloride ($SO_2Cl_2$,which is $Y$).$SO_2$ $(X)$ $+ Cl_2 \xrightarrow{	ext{Wood charcoal}} SO_2Cl_2$ $(Y)$Therefore,$X$ is $SO_2$ and $Y$ is $SO_2Cl_2$.

White phosphorus reacts with sulphuryl chloride to form $PCl_5$ and $X$. Chlorine reacts with $X$ in the presence of wood charcoal to form $Y$. $X$ and $Y$ are respectively

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