Why can't the efficiency of a heat engine ever be $100 \%$?

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(N/A) The efficiency of a heat engine is defined as $\eta = 1 - \frac{Q_2}{Q_1}$,where $Q_1$ is the heat absorbed from the source and $Q_2$ is the heat rejected to the sink.
According to the Second Law of Thermodynamics (Kelvin-Planck statement),it is impossible to construct a device that operates in a cycle and produces no effect other than the extraction of heat from a single reservoir and the performance of an equivalent amount of work.
For the efficiency to be $100 \%$,$Q_2$ must be $0$,meaning all heat absorbed from the source is converted into work.
This would require the sink temperature to be absolute zero $(0 \ K)$,which is unattainable according to the Third Law of Thermodynamics.
Therefore,some amount of heat must always be rejected to the sink,making $100 \%$ efficiency impossible.

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Why is a heat engine never $100\%$ efficient?

Find the change in the entropy in the following process: $100 \, g$ of ice at $0^{\circ}C$ melts when dropped in a bucket of water at $50^{\circ}C$. (Assume the temperature of the water does not change). The result is in $cal/K$.

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When $1\, kg$ of ice at $0^\circ C$ melts to water at $0^\circ C,$ the resulting change in its entropy,taking latent heat of ice to be $80\, cal/g,$ is ...... $cal/K$.

Entropy of a system decreases .........

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