Why does the compound $(A)$ given below not form an oxime?
(N/A) The formation of an oxime requires a free carbonyl group (aldehyde or ketone) to react with hydroxylamine $(NH_2OH)$.
In the given structure,the glucose derivative is in its cyclic hemiacetal form where the anomeric carbon is involved in the ring structure.
Furthermore,the hydroxyl groups are acetylated $(OAc)$.
Since there is no free aldehyde or ketone group available in the cyclic structure,it cannot react with hydroxylamine to form an oxime.
In the given structure,the glucose derivative is in its cyclic hemiacetal form where the anomeric carbon is involved in the ring structure.
Furthermore,the hydroxyl groups are acetylated $(OAc)$.
Since there is no free aldehyde or ketone group available in the cyclic structure,it cannot react with hydroxylamine to form an oxime.
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