Why is walking barefooted on a sharp gravel (grit) road difficult?
(N/A) Pressure is defined as force per unit area $(P = F/A)$.
When walking barefoot on sharp gravel,the contact area $(A)$ between the feet and the sharp edges of the stones is extremely small.
Since the pressure is inversely proportional to the area $(P \propto 1/A)$,a very small area results in a very high surface pressure.
This high pressure exerted on the skin of the feet causes pain,making it difficult to walk.
When walking barefoot on sharp gravel,the contact area $(A)$ between the feet and the sharp edges of the stones is extremely small.
Since the pressure is inversely proportional to the area $(P \propto 1/A)$,a very small area results in a very high surface pressure.
This high pressure exerted on the skin of the feet causes pain,making it difficult to walk.
Explore More
Similar Questions
In the previous problem,if $15.0 \; cm$ of water and spirit each are further poured into the respective arms of the tube,what is the difference in the levels of mercury in the two arms (in $; cm$)? (Specific gravity of mercury $= 13.6$)
Medium
View SolutionAt a depth of $1000 \; m$ in an ocean:
$(a)$ What is the absolute pressure?
$(b)$ What is the gauge pressure?
$(c)$ Find the force acting on the window of area $20 \; cm \times 20 \; cm$ of a submarine at this depth,the interior of which is maintained at sea-level atmospheric pressure. (The density of sea water is $1.03 \times 10^3 \; kg \; m^{-3}$,$g = 10 \; m \; s^{-2}$.)
$(a)$ What is the absolute pressure?
$(b)$ What is the gauge pressure?
$(c)$ Find the force acting on the window of area $20 \; cm \times 20 \; cm$ of a submarine at this depth,the interior of which is maintained at sea-level atmospheric pressure. (The density of sea water is $1.03 \times 10^3 \; kg \; m^{-3}$,$g = 10 \; m \; s^{-2}$.)
Medium
View SolutionThree identical vessels are filled up to the same height with three different liquids $A, B$ and $C$ of densities $\rho_A, \rho_B$ and $\rho_C$ (where $\rho_A > \rho_B > \rho_C$). The pressure at the bottom of the vessels is:
What is atmospheric pressure?
Easy
View SolutionTwo vessels have the same base area but different shapes. The first vessel takes twice the volume of water that the second vessel requires to fill up to a particular common height. Is the force exerted by the water on the base of the vessel the same in the two cases? If so,why do the vessels filled with water to that same height give different readings on a weighing scale?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo