Why on dilution the Lambda_m of CH_3COOH incr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $CH_3COOH$ is a weak electrolyte,which undergoes partial dissociation in solution.
On dilution,the degree of dissociation $(\alpha)$ increases si

Vedclass · Accepted Answer

$CH_3COOH$ is a weak electrolyte,while $CH_3COONa$ is a strong electrolyte.

Vedclass · Answer

(A) $CH_3COOH$ is a weak electrolyte,which undergoes partial dissociation in solution.
On dilution,the degree of dissociation $(\alpha)$ increases significantly according to Ostwald's dilution law,leading to a sharp increase in the number of ions and thus a drastic increase in molar conductivity $(\Lambda_m)$.
$CH_3COONa$ is a strong electrolyte,which is already completely dissociated in solution.
On dilution,the number of ions remains constant,and the increase in $\Lambda_m$ is only due to the decrease in inter-ionic attractions,which results in a gradual increase.

Why on dilution the $\Lambda_m$ of $CH_3COOH$ increases drastically,while that of $CH_3COONa$ increases gradually?

Similar Questions

Which species is obtained at the anode during the electrolysis of an aqueous solution containing a higher concentration of $H_2SO_4$?

In the process of electrolysis,the current is carried out inside the electrolyte by

The cell used for the electrolysis of fused $NaCl$ is

During the electrolysis of fused $NaCl$,the product obtained at anode is

$KOOC-CH_2-CH_2-COOK \xrightarrow{\text{electrolysis}} (A) (\text{major})$. Product $(A)$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module