Why is the value of $g$ greater at the poles than at the equator?

(N/A) The Earth is not a perfect sphere; it is flattened at the poles and bulges at the equator. The acceleration due to gravity is given by the formula $g = \frac{GM}{R^2}$,where $G$ is the gravitational constant,$M$ is the mass of the Earth,and $R$ is the radius of the Earth. Since the radius $R$ is smaller at the poles compared to the equator,the value of $g$ is inversely proportional to the square of the radius,making $g$ greater at the poles.