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(B) The energy of an electron in the $n^{th}$ orbit of a hydrogen atom is given by $E_n = -\frac{13.6}{n^2} \ eV$. The energy difference between two a

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decreases

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(B) The energy of an electron in the $n^{th}$ orbit of a hydrogen atom is given by $E_n = -\frac{13.6}{n^2} \ eV$. The energy difference between two adjacent levels $n$ and $n+1$ is given by $\Delta E = E_{n+1} - E_n = 13.6 \left( \frac{1}{n^2} - \frac{1}{(n+1)^2} \right) \ eV$. As the principal quantum number $n$ increases,the term $\left( \frac{1}{n^2} - \frac{1}{(n+1)^2} \right)$ decreases. Therefore,the energy difference between adjacent energy levels decreases as $n$ increases.

With increasing principal quantum number,the energy difference between adjacent energy levels in $H$ atom

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