With respect to air,the critical angle in a m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The critical angle $C$ is given by the formula $\sin C = \frac{1}{n}$,where $n$ is the refractive index of the medium.Since the refractive index $

Vedclass · Accepted Answer

less than $	heta$

Vedclass · Answer

(C) The critical angle $C$ is given by the formula $\sin C = \frac{1}{n}$,where $n$ is the refractive index of the medium.Since the refractive index $n$ is inversely proportional to the wavelength $\lambda$ (Cauchy's relation: $n \approx A + \frac{B}{\lambda^2}$),as the wavelength decreases,the refractive index increases.For red light,the wavelength is $\lambda_1$. For yellow light,the wavelength is $\lambda_2$. Since $\lambda_1 > \lambda_2$,the refractive index for red light $(n_r)$ is less than the refractive index for yellow light $(n_y)$.Therefore,$n_r Since $\sin C = \frac{1}{n}$,a higher refractive index results in a smaller critical angle.Thus,the critical angle for yellow light will be less than the critical angle for red light $(	heta)$.

With respect to air,the critical angle in a medium for red light of wavelength $\lambda_1$ is $\theta$. Other facts remaining same,the critical angle for yellow light of wavelength $\lambda_2$ will be

Similar Questions

Total internal reflection of a ray of light is possible when the ($i_c$ = critical angle,$i$ = angle of incidence)

For a given pair of transparent media,the critical angle is maximum for which colour?

Brilliance of diamond is due to

$A$ ray of light refracts from medium $1$ into a thin layer of medium $2$, crosses the layer, and is incident at the critical angle on the interface between medium $2$ and $3$ as shown in the figure. If the angle of incidence of the ray is $\theta$, the value of $\theta$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module