With respect to the usual notations of an A.P | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The sum of the first $n$ terms of an $A.P.$ is given by the formula:$S_n = \frac{n}{2} [2a + (n-1)d]$Given values are $a = 3$,$n = 8$,and $S_n = 1

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) The sum of the first $n$ terms of an $A.P.$ is given by the formula:$S_n = \frac{n}{2} [2a + (n-1)d]$Given values are $a = 3$,$n = 8$,and $S_n = 192$.Substituting these values into the formula:$192 = \frac{8}{2} [2(3) + (8-1)d]$$192 = 4 [6 + 7d]$Divide both sides by $4$:$48 = 6 + 7d$$48 - 6 = 7d$$42 = 7d$$d = \frac{42}{7} = 6$Therefore,the common difference $d$ is $6$.

With respect to the usual notations of an $A.P.$,if $a=3, n=8$ and $S_{n}=192$,find the common difference $d$.

Similar Questions

The sum of the first $15$ terms of the $A.P.$ $-10, -12, -14, -16, \ldots$ is:

Find the sum given below: $-5 + (-8) + (-11) + \ldots + (-230)$

$7+12+17+\ldots+102 = \ldots$

If $a=2$ and $d=4,$ then $S_{40}=\ldots \ldots \ldots$

In an $AP$,if $S_{n} = 3n^{2} + 5n$ and $a_{k} = 164$,find the value of $k$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module