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(A) $1$. From reaction $(I)$,$B + ANO_3 \longrightarrow BNO_3 + A$,metal $B$ displaces $A$ from its salt solution,so $B$ is more reactive than $A$ $(B

Vedclass · Accepted Answer

$B > A > D > E$

Vedclass · Answer

(A) $1$. From reaction $(I)$,$B + ANO_3 \longrightarrow BNO_3 + A$,metal $B$ displaces $A$ from its salt solution,so $B$ is more reactive than $A$ $(B > A)$.$2$. From reaction $(II)$,$A + HCl \longrightarrow ACl + \frac{1}{2} H_2$,metal $A$ reacts with $HCl$ to evolve $H_2$ gas,meaning $A$ is more reactive than $H$ $(A > H)$.$3$. From reaction $(III)$,$D + ECl \longrightarrow DCl + E$,metal $D$ displaces $E$ from its salt solution,so $D$ is more reactive than $E$ $(D > E)$.$4$. From reaction $(IV)$,$D + HNO_3$ does not evolve $H_2$ gas,which is typical for metals less reactive than $H$ (or metals that act as reducing agents for $HNO_3$),implying $D $5$. Combining these: $B > A > H > D > E$. Thus,the decreasing order of reactivity is $B > A > D > E$.

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