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(B) The sensitivity of a potentiometer is defined as the smallest potential difference that can be measured by it.The potential gradient $(k)$ is defi

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$A$ and $C$ only

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(B) The sensitivity of a potentiometer is defined as the smallest potential difference that can be measured by it.The potential gradient $(k)$ is defined as the potential drop per unit length of the wire,given by $k = V/L$.Sensitivity is inversely proportional to the potential gradient $(k)$. Therefore,as $k$ decreases,the sensitivity increases.Since $k = V/L$,decreasing $k$ is equivalent to increasing the length $(L)$ of the potentiometer wire for a fixed potential difference $(V)$.Thus,sensitivity is directly proportional to the length $(L)$ of the wire and inversely proportional to the potential gradient $(k)$.Statements $(A)$ and $(C)$ are correct.

Similar Questions

$A$ cell is connected to a potentiometer, and the balance point is obtained at a length of $2 \, m$. When a resistance of $5 \, \Omega$ is connected in parallel with the cell, the balance point is obtained at a length of $3 \, m$. What is the internal resistance of the cell in $\Omega$?

$A$ voltmeter reads the potential difference across the terminals of an old battery as $1.2 \, V$,while a potentiometer reads $1.4 \, V$. The internal resistance of the battery is $40 \, \Omega$. What is the resistance of the voltmeter in $\Omega$?

$A$ wire of length $10 \ cm$ is connected to a cell of $emf$ $2 \ V$ and negligible internal resistance. The resistance of the wire is $3 \ \Omega$. The value of the series resistance required to obtain a potential gradient of $10 \ mV/cm$ is ................ $\Omega$.

Sensitivity of a given potentiometer can be decreased by

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