With the help of the remainder theorem,find t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$p(x) = x^{3} + x^{2} - 26x + 24$ a

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) According to the remainder theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$p(x) = x^{3} + x^{2} - 26x + 24$ and the divisor is $(x - 1)$,so $a = 1$.To find the remainder,we calculate $p(1)$:$p(1) = (1)^{3} + (1)^{2} - 26(1) + 24$$p(1) = 1 + 1 - 26 + 24$$p(1) = 2 - 26 + 24$$p(1) = -24 + 24 = 0$.Therefore,the remainder is $0$.

With the help of the remainder theorem,find the remainder when the polynomial $p(x) = x^{3} + x^{2} - 26x + 24$ is divided by the divisor $x - 1$.

Similar Questions

Factorise the following:
$9 x^{2}-12 x+3$

Factorise: $6x^2 + 5x - 6$

Factorise $49 x^{2}-35 x+6$.

Find the remainder obtained on dividing $p(x) = x^3 + 1$ by $x + 1$.

Factorise: $x^{3}+x^{2}-4x-4$

Vedclass Test Series

Exam Paper Generator

Online Exam Module