The word '$UNIVERSITY$' is arranged randomly. Then the probability that both '$I$'s do not come together is:

  • A
    $\frac{3}{5}$
  • B
    $\frac{2}{5}$
  • C
    $\frac{4}{5}$
  • D
    $\frac{1}{5}$

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If $A$ and $B$ are two events such that $A \subseteq B,$ then $P\left( \frac{B}{A} \right) = $

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