$\angle A$ के सभी अन्य त्रिकोणमितीय अनुपातों को $\sec A$ के पदों में लिखिए।

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हम जानते हैं कि,$\cos A = \frac{1}{\sec A}$।
सर्वसमिका $\sin^2 A + \cos^2 A = 1$ का उपयोग करते हुए,$\sin^2 A = 1 - \cos^2 A = 1 - \frac{1}{\sec^2 A} = \frac{\sec^2 A - 1}{\sec^2 A}$ प्राप्त होता है।
अतः,$\sin A = \frac{\sqrt{\sec^2 A - 1}}{\sec A}$।
सर्वसमिका $\tan^2 A + 1 = \sec^2 A$ का उपयोग करते हुए,$\tan^2 A = \sec^2 A - 1$ प्राप्त होता है।
अतः,$\tan A = \sqrt{\sec^2 A - 1}$।
चूंकि $\cot A = \frac{1}{\tan A}$,इसलिए $\cot A = \frac{1}{\sqrt{\sec^2 A - 1}}$।
चूंकि $\operatorname{cosec} A = \frac{1}{\sin A}$,इसलिए $\operatorname{cosec} A = \frac{\sec A}{\sqrt{\sec^2 A - 1}}$।

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यदि $\sec \theta = \frac{5}{3}$ है,तो $\tan \theta = \ldots$

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सिद्ध कीजिए कि:
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