Write the bond angle and hybridization type of the water molecule.
(N/A) In the water molecule $(H_2O)$,the oxygen atom is $sp^3$ hybridized.
It has two bond pairs and two lone pairs of electrons,resulting in a bent ($V$-shaped) geometry.
Due to the presence of two lone pairs on the oxygen atom,the bond angle is compressed from the ideal tetrahedral angle of $109.5^{\circ}$ to $104.5^{\circ}$.
It has two bond pairs and two lone pairs of electrons,resulting in a bent ($V$-shaped) geometry.
Due to the presence of two lone pairs on the oxygen atom,the bond angle is compressed from the ideal tetrahedral angle of $109.5^{\circ}$ to $104.5^{\circ}$.
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Similar Questions
Choose the correct statement:
"Hybridisation of central atom does not always change due to back bonding". This statement is valid for which of the following compounds?
$(i)$ $CCl_3^-$ $(ii)$ $CCl_2$ $(iii)$ $(SiH_3)_2O$ $(iv)$ $N(SiH_3)_3$
$(i)$ $CCl_3^-$ $(ii)$ $CCl_2$ $(iii)$ $(SiH_3)_2O$ $(iv)$ $N(SiH_3)_3$
The hybridisation of the central atom $I$ in $IF_7$ is:
Identify the pair of molecules in which the hybridization of the central atom is $sp^2$ with bent geometry.
Which of the following processes involves a change in bond angle along with a change in hybridization?
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