Write the degree of freedom for a polyatomic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The degree of freedom $(f)$ of a gas molecule is defined as the number of independent ways in which a molecule can possess energy.For a non-linear

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) The degree of freedom $(f)$ of a gas molecule is defined as the number of independent ways in which a molecule can possess energy.For a non-linear polyatomic gas molecule,there are $3$ translational degrees of freedom and $3$ rotational degrees of freedom.Therefore,the total degree of freedom for a non-linear polyatomic gas is $f = 3 + 3 = 6$.If the polyatomic gas is linear,it has $3$ translational and $2$ rotational degrees of freedom,resulting in $f = 5$ (at room temperature).In general,for a non-linear polyatomic molecule,the degree of freedom is $6$.

Write the degree of freedom for a polyatomic gas.

Similar Questions

Supposing the distance between the atoms of a diatomic gas to be constant,its specific heat at constant volume per mole (gram mole) is

An ideal gas has molecules with $5$ degrees of freedom. The ratio of specific heats at constant pressure $(C_p)$ and at constant volume $(C_v)$ is

If the degrees of freedom of a gas molecule is $6$,then the total internal energy of the gas molecule at a temperature of $47^{\circ} C$ (in $eV$) is (Boltzmann constant $= 1.38 \times 10^{-23} \ J \ K^{-1}$)

For a triatomic gas molecule,if the degrees of freedom for translation,rotation,and vibration are considered,then $C_P/C_V = ?$

When the temperature of a gas is increased,does the degree of freedom change?

Vedclass Test Series

Exam Paper Generator

Online Exam Module