Write the differential rate expression for the following reactions and determine their order of reaction:
$1) \ 2 \ HI \rightarrow H_2 + I_2$
$2) \ 2 \ NO_{(g)} + O_{2(g)} \rightarrow 2 \ NO_{2(g)}$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) For a general reaction $aA + bB \rightarrow \text{products}$,the differential rate expression is given by $Rate = -\frac{1}{a} \frac{d[A]}{dt} = -\frac{1}{b} \frac{d[B]}{dt}$.
$1) \ 2 \ HI \rightarrow H_2 + I_2$
Differential rate expression: $Rate = -\frac{1}{2} \frac{d[HI]}{dt} = \frac{d[H_2]}{dt} = \frac{d[I_2]}{dt}$.
Order of reaction: This is a decomposition reaction which is experimentally found to be of $0^{th}$ order with respect to $HI$ at high concentrations,but generally,for such elementary reactions,it is considered $2^{nd}$ order. However,based on standard textbook examples,it is often cited as $2^{nd}$ order.
$2) \ 2 \ NO_{(g)} + O_{2(g)} \rightarrow 2 \ NO_{2(g)}$
Differential rate expression: $Rate = -\frac{1}{2} \frac{d[NO]}{dt} = -\frac{d[O_2]}{dt} = \frac{1}{2} \frac{d[NO_2]}{dt}$.
Order of reaction: This is a $3^{rd}$ order reaction ($2^{nd}$ order with respect to $NO$ and $1^{st}$ order with respect to $O_2$).

Explore More

Similar Questions

$A$ reaction is first order in terms of $A$ and second order in terms of $B$. What will be the rate of reaction,if the concentration of $B$ is increased two times?

Rate of reaction for $2X + Y \rightarrow 3W + Z$ is $1.2 \times 10^{-4} \ mol \ dm^{-3} \ sec^{-1}$ when $[X] = [Y] = 0.6 \ mol \ dm^{-3}$. Calculate the value of the rate constant if the reaction is first order in $X$ and zero order in $Y$.

The number of incorrect statement/s from the following is:
$A$. The successive half-lives of zero-order reactions decrease with time.
$B$. $A$ substance appearing as a reactant in the chemical equation may not affect the rate of reaction.
$C$. Order and molecularity of a chemical reaction can be a fractional number.
$D$. The rate constant units of zero and second-order reactions are $mol \ L^{-1} s^{-1}$ and $mol^{-1} L s^{-1}$ respectively.

The rate of reaction between two reactants $A$ and $B$ decreases by a factor of $4$ if the concentration of reactant $B$ is doubled. The order of this reaction with respect to reactant $B$ is

For a reaction,$A + 2B \longrightarrow C$,the rate is given by $+\frac{d[C]}{dt} = k[A][B]$. Hence,the order of the reaction is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo