Write down the Boolean expression for the out | vedclass

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(A) $1$. The inputs $A$ and $B$ pass through $NOT$ gates, resulting in $\overline{ A }$ and $\overline{ B }$ respectively.$2$. These two outputs ($\ov

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$\overline{ A } \cdot \overline{ B } + A \cdot B$

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(A) $1$. The inputs $A$ and $B$ pass through $NOT$ gates, resulting in $\overline{ A }$ and $\overline{ B }$ respectively.$2$. These two outputs ($\overline{ A }$ and $\overline{ B }$) are fed into an $AND$ gate, producing $\overline{ A } \cdot \overline{ B }$.$3$. The original inputs $A$ and $B$ are fed directly into another $AND$ gate, producing $A \cdot B$.$4$. Finally, the outputs of these two $AND$ gates are fed into an $OR$ gate.$5$. Therefore, the final output expression is $Y = \overline{ A } \cdot \overline{ B } + A \cdot B$.

Write down the Boolean expression for the output $Y$ of the logic circuit shown in the figure.

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