Write the following equation in the standard form $ax + by + c = 0$ and indicate the values of $a, b,$ and $c$ in each case:
$0.2x + 0.5y = 1.2$
$0.2x + 0.5y = 1.2$
(N/A) The given equation is $0.2x + 0.5y = 1.2$.
To write this in the standard form $ax + by + c = 0$,we subtract $1.2$ from both sides:
$0.2x + 0.5y - 1.2 = 0$.
Comparing this with the standard form $ax + by + c = 0$,we get:
$a = 0.2$
$b = 0.5$
$c = -1.2$
To write this in the standard form $ax + by + c = 0$,we subtract $1.2$ from both sides:
$0.2x + 0.5y - 1.2 = 0$.
Comparing this with the standard form $ax + by + c = 0$,we get:
$a = 0.2$
$b = 0.5$
$c = -1.2$
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