Write the first four terms of the $AP,$ when the first term $a$ and the common difference $d$ are given as follows: $a=4, d=-3.$
(A) Given: First term $a = 4$ and common difference $d = -3.$
The general form of an $AP$ is $a, a+d, a+2d, a+3d, \dots$
First term $a_1 = a = 4.$
Second term $a_2 = a + d = 4 + (-3) = 4 - 3 = 1.$
Third term $a_3 = a + 2d = 4 + 2(-3) = 4 - 6 = -2.$
Fourth term $a_4 = a + 3d = 4 + 3(-3) = 4 - 9 = -5.$
Therefore,the first four terms of the $AP$ are $4, 1, -2, -5.$
The general form of an $AP$ is $a, a+d, a+2d, a+3d, \dots$
First term $a_1 = a = 4.$
Second term $a_2 = a + d = 4 + (-3) = 4 - 3 = 1.$
Third term $a_3 = a + 2d = 4 + 2(-3) = 4 - 6 = -2.$
Fourth term $a_4 = a + 3d = 4 + 3(-3) = 4 - 9 = -5.$
Therefore,the first four terms of the $AP$ are $4, 1, -2, -5.$
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