Write the Nernst equation for the anode and cathode of a Daniell cell.
For the Daniell cell,the anode reaction is $Zn_{(s)} \rightarrow Zn^{2+}_{(aq)} + 2e^-$. The Nernst equation for the anode is: $E_{Zn^{2+}/Zn} = E^{\circ}_{Zn^{2+}/Zn} - \frac{RT}{2F} \ln \frac{1}{[Zn^{2+}]}$.
The cathode reaction is $Cu^{2+}_{(aq)} + 2e^- \rightarrow Cu_{(s)}$. The Nernst equation for the cathode is: $E_{Cu^{2+}/Cu} = E^{\circ}_{Cu^{2+}/Cu} - \frac{RT}{2F} \ln \frac{1}{[Cu^{2+}]}$.
The cathode reaction is $Cu^{2+}_{(aq)} + 2e^- \rightarrow Cu_{(s)}$. The Nernst equation for the cathode is: $E_{Cu^{2+}/Cu} = E^{\circ}_{Cu^{2+}/Cu} - \frac{RT}{2F} \ln \frac{1}{[Cu^{2+}]}$.
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