State the principle of superposition of waves.
(N/A) The principle of superposition states that when two or more waves travel through a medium simultaneously,each wave acts independently of the others. The resultant displacement $y$ at any point and at any instant is the algebraic sum of the individual displacements $y_1, y_2, y_3, \dots$ produced by each wave at that point.
Mathematically,it is expressed as: $y = y_1 + y_2 + y_3 + \dots = \sum_{i=1}^{n} y_i$.
Mathematically,it is expressed as: $y = y_1 + y_2 + y_3 + \dots = \sum_{i=1}^{n} y_i$.
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Similar Questions
Two waves represented by $y_1 = 10 \sin(200\pi t)$ and $y_2 = 20 \sin(200\pi t + \pi/2)$ are superimposed at any point at a particular instant. The amplitude of the resultant wave is:
Medium
View SolutionThe equations of two waves are given as
$\begin{aligned}
& y_1=a \sin \left(\omega t+\phi_1\right) \\
& y_2=a \sin \left(\omega t+\phi_2\right)
\end{aligned}$
If the amplitude and time period of the resultant wave are the same as those of the individual waves,then $(\phi_1-\phi_2)$ is
$\begin{aligned}
& y_1=a \sin \left(\omega t+\phi_1\right) \\
& y_2=a \sin \left(\omega t+\phi_2\right)
\end{aligned}$
If the amplitude and time period of the resultant wave are the same as those of the individual waves,then $(\phi_1-\phi_2)$ is
Two waves with same amplitude and frequency superpose at a point. The ratio of resultant intensities when they arrive in phase to that when they arrive $90^{\circ}$ out of phase is $\left[\cos \frac{\pi}{2}=0\right]$
Two loudspeakers $L_1$ and $L_2$,driven by a common oscillator and amplifier,are arranged as shown. The frequency of the oscillator is gradually increased from zero,and the detector at $D$ records a series of maxima and minima. If the speed of sound is $330 \, m/s$,then the frequency at which the first maximum is observed is .... $Hz$.
Medium
View SolutionIf two waves of the same frequency and amplitude on superposition produce a resultant disturbance of the same amplitude,the waves differ in phase by
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