What is the approximate ratio of the mass of | vedclass

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(A) The mass of an electron is approximately $m_e \approx 9.1 	imes 10^{-31} \,kg$.The mass of the observable universe is approximately $M_u \approx

Vedclass · Accepted Answer

$10^{85}$

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(A) The mass of an electron is approximately $m_e \approx 9.1 	imes 10^{-31} \,kg$.The mass of the observable universe is approximately $M_u \approx 10^{55} \,kg$.The ratio of the mass of the observable universe to the mass of an electron is given by:Ratio $= \frac{M_u}{m_e} \approx \frac{10^{55}}{10^{-31}} = 10^{55 - (-31)} = 10^{86}$.Rounding to the nearest order of magnitude, the ratio is approximately $10^{85}$.

What is the approximate ratio of the mass of the observable universe to the mass of an electron?

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