Write structures of different isomers corresponding to the $5^{th}$ member of alkyne series. Also write $IUPAC$ names of all the isomers. What type of isomerism is exhibited by different pairs of isomers?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The $5^{th}$ member of the alkyne series follows the general formula $C_nH_{2n-2}$. For $n=6$,the molecular formula is $C_6H_{10}$.
The possible isomers are:
$(a)$ $HC\equiv C-CH_2-CH_2-CH_2-CH_3$: $Hex-1-yne$
$(b)$ $CH_3-C\equiv C-CH_2-CH_2-CH_3$: $Hex-2-yne$
$(c)$ $CH_3-CH_2-C\equiv C-CH_2-CH_3$: $Hex-3-yne$
$(d)$ $HC\equiv C-CH(CH_3)-CH_2-CH_3$: $3-Methylpent-1-yne$
$(e)$ $HC\equiv C-CH_2-CH(CH_3)-CH_3$: $4-Methylpent-1-yne$
$(f)$ $CH_3-C\equiv C-CH(CH_3)-CH_3$: $4-Methylpent-2-yne$
$(g)$ $HC\equiv C-C(CH_3)_2-CH_3$: $3,3-Dimethylbut-1-yne$
These isomers exhibit position isomerism (due to the change in the position of the triple bond) and chain isomerism (due to the difference in the carbon chain structure).

Explore More

Similar Questions

But$-1-$yne on reaction with dil. $H_2SO_4$ in the presence of $Hg^{2+}$ ions at $333 \ K$ gives:

Acetylene reacts with a $42\% H_2SO_4$ solution containing $1\% HgSO_4$ to give

The distinguishing test for a triple bond containing acidic hydrogen is:

Which of the following reagents will be able to distinguish between $but-1-yne$ and $but-2-yne$?

$CH_3COOH$ is reacted with $CH \equiv CH$ in the presence of $Hg^{2+}$,the product is:

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo