Write the atomic numbers of two elements $X$ and $Y$ having electronic configurations $2, 8, 2$ and $2, 8, 6$ respectively.
(N/A) The atomic number of an element is equal to the total number of electrons present in its neutral atom.
For element $X$,the electronic configuration is $2, 8, 2$. The total number of electrons is $2 + 8 + 2 = 12$. Therefore,the atomic number of $X$ is $12$.
For element $Y$,the electronic configuration is $2, 8, 6$. The total number of electrons is $2 + 8 + 6 = 16$. Therefore,the atomic number of $Y$ is $16$.
For element $X$,the electronic configuration is $2, 8, 2$. The total number of electrons is $2 + 8 + 2 = 12$. Therefore,the atomic number of $X$ is $12$.
For element $Y$,the electronic configuration is $2, 8, 6$. The total number of electrons is $2 + 8 + 6 = 16$. Therefore,the atomic number of $Y$ is $16$.
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