(B) The given polynomial is $p(x) = x^{3} + 27$.To find the coefficient of $x^{2}$,we can rewrite the polynomial as $p(x) = 1 \cdot x^{3} + 0 \cdot x^

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(B) The given polynomial is $p(x) = x^{3} + 27$.To find the coefficient of $x^{2}$,we can rewrite the polynomial as $p(x) = 1 \cdot x^{3} + 0 \cdot x^{2} + 0 \cdot x + 27$.Comparing this with the standard form,the term containing $x^{2}$ is $0 \cdot x^{2}$.Therefore,the coefficient of $x^{2}$ is $0$.