Write the condition of destructive interference in terms of path and phase difference.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) For destructive interference to occur, the waves must arrive at a point in opposite phase.
$1$. Phase difference $(\Delta \phi)$: The phase difference must be an odd multiple of $\pi$. Mathematically, $\Delta \phi = (2n + 1)\pi$, where $n = 0, 1, 2, 3, \dots$.
$2$. Path difference $(\Delta x)$: Since the relation between path difference and phase difference is $\Delta \phi = \frac{2\pi}{\lambda} \Delta x$, we substitute the condition for destructive interference:
$(2n + 1)\pi = \frac{2\pi}{\lambda} \Delta x$
$\Delta x = (2n + 1) \frac{\lambda}{2}$, where $n = 0, 1, 2, 3, \dots$.

Explore More

Similar Questions

Diffraction and interference of light suggest

Light waves from two coherent sources arrive at two points on a screen with path difference of zero and $\lambda / 2$. The ratio of the intensities at the points is

To observe a stationary interference pattern formed by two light waves,it is not necessary that they must have :

Define constructive interference. $OR$ Define destructive interference.

The interference pattern is obtained with two coherent light sources of intensity ratio $4:1$. If the ratio $\frac{I_{\max} + I_{\min}}{I_{\max} - I_{\min}}$ is $\frac{5}{x}$,then the value of $x$ will be equal to:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo