Write the first five terms of the sequence wh | vedclass

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(A) Substituting $n = 1, 2, 3, 4, 5$ in the formula $a_{n} = \frac{2n - 3}{6}$,we get:$a_{1} = \frac{2(1) - 3}{6} = \frac{-1}{6}$$a_{2} = \frac{2(2) -

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$-\frac{1}{6}, \frac{1}{6}, \frac{1}{2}, \frac{5}{6}, \frac{7}{6}$

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(A) Substituting $n = 1, 2, 3, 4, 5$ in the formula $a_{n} = \frac{2n - 3}{6}$,we get:$a_{1} = \frac{2(1) - 3}{6} = \frac{-1}{6}$$a_{2} = \frac{2(2) - 3}{6} = \frac{1}{6}$$a_{3} = \frac{2(3) - 3}{6} = \frac{3}{6} = \frac{1}{2}$$a_{4} = \frac{2(4) - 3}{6} = \frac{5}{6}$$a_{5} = \frac{2(5) - 3}{6} = \frac{7}{6}$Thus,the first five terms are $-\frac{1}{6}, \frac{1}{6}, \frac{1}{2}, \frac{5}{6}, \frac{7}{6}$.

Write the first five terms of the sequence whose $n^{th}$ term is $a_{n} = \frac{2n - 3}{6}$.

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