Write the following set in the set-builder form: $\{ 3, 6, 9, 12 \}$

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(N/A) The given set is $A = \{ 3, 6, 9, 12 \}$.
We observe that each element is a multiple of $3$ and can be written as $3n$,where $n$ is a natural number.
For $n=1$,$3(1) = 3$.
For $n=2$,$3(2) = 6$.
For $n=3$,$3(3) = 9$.
For $n=4$,$3(4) = 12$.
Thus,the set can be written in set-builder form as $\{ x : x = 3n, n \in \mathbb{N} \text{ and } 1 \le n \le 4 \}$.

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