Write the isomers of the compound having formula $C_4H_9Br$.

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Solution

(N/A) There are four structural isomers for the compound with the molecular formula $C_4H_9Br$:
$(a)$ $1-Bromobutane$: $CH_3-CH_2-CH_2-CH_2-Br$
$(b)$ $2-Bromobutane$: $CH_3-CH_2-CH(Br)-CH_3$
$(c)$ $1-Bromo-2-methylpropane$: $(CH_3)_2CH-CH_2-Br$
$(d)$ $2-Bromo-2-methylpropane$: $(CH_3)_3C-Br$

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Chapter

Haloalkanes and Haloarenes

Subtopic

Introduction of Halogen containing compounds

Match the structures given in Column-$(I)$ with their types in Column-$(II)$.
Column-$(I)$ (Structure) Column-$(II)$ (Type)
$(A)$ Cyclohexadiene with $-X$ $(i)$ Dihaloarene
$(B)$ $p$-Dihalobenzene $(ii)$ Trihaloarene
$(C)$ $1,3,5$-Trihalobenzene $(iii)$ Tetrahaloarene
$(D)$ Chlorobenzene $(iv)$ Monohaloarene
$(v)$ Monochloroarene
$(vi)$ Dichloroarene

Column-$(I)$ (Structure)	Column-$(II)$ (Type)
$(A)$ Cyclohexadiene with $-X$	$(i)$ Dihaloarene
$(B)$ $p$-Dihalobenzene	$(ii)$ Trihaloarene
$(C)$ $1,3,5$-Trihalobenzene	$(iii)$ Tetrahaloarene
$(D)$ Chlorobenzene	$(iv)$ Monohaloarene
	$(v)$ Monochloroarene
	$(vi)$ Dichloroarene