Write the main product of the given reactions:
$(1)$ $CH_3CH = CHCH_3 + HBr \to$
$(2)$ $CH_3-C(CH_3)=CH_2 + HBr \to$
$(1)$ $CH_3CH = CHCH_3 + HBr \to$
$(2)$ $CH_3-C(CH_3)=CH_2 + HBr \to$
(N/A) The addition of $HBr$ to alkenes follows Markovnikov's rule,where the electrophile $(H^+)$ adds to the carbon with more hydrogen atoms,and the nucleophile $(Br^-)$ adds to the carbon with fewer hydrogen atoms.
$(1)$ For $CH_3CH = CHCH_3 + HBr \to CH_3CH_2-CH(Br)-CH_3$ ($2$-Bromobutane).
$(2)$ For $CH_3-C(CH_3)=CH_2 + HBr \to CH_3-C(Br)(CH_3)-CH_3$ ($2$-Bromo-$2$-methylpropane).
$(1)$ For $CH_3CH = CHCH_3 + HBr \to CH_3CH_2-CH(Br)-CH_3$ ($2$-Bromobutane).
$(2)$ For $CH_3-C(CH_3)=CH_2 + HBr \to CH_3-C(Br)(CH_3)-CH_3$ ($2$-Bromo-$2$-methylpropane).
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Similar Questions
The major product of the reaction is:
Difficult
View SolutionGiven below are two statements.
Statement $I :$ The presence of weaker $\pi$-bonds makes alkenes less stable than alkanes.
Statement $II :$ The strength of the double bond is greater than that of carbon-carbon single bond.
In the light of the above statements,choose the correct answer from the options given below.
Statement $I :$ The presence of weaker $\pi$-bonds makes alkenes less stable than alkanes.
Statement $II :$ The strength of the double bond is greater than that of carbon-carbon single bond.
In the light of the above statements,choose the correct answer from the options given below.
The major product $[B]$ in the following sequence of reactions is
$CH_3-C(CH(CH_3)_2)=CH-CH_2CH_3$ $\xrightarrow[(i) B_2H_6]{(ii) H_2O_2, OH^{-}} [A]$ $\xrightarrow[\Delta]{dil. H_2SO_4} [B]$
$CH_3-C(CH(CH_3)_2)=CH-CH_2CH_3$ $\xrightarrow[(i) B_2H_6]{(ii) H_2O_2, OH^{-}} [A]$ $\xrightarrow[\Delta]{dil. H_2SO_4} [B]$
DifficultJEE MAIN 2020
View SolutionOn reaction with hot conc. $H_2SO_4$,which one of the following compounds loses a molecule of water?
Medium
View Solution$2$-Butanol $\xrightarrow[\Delta]{H^{+}}$ Products. If all products formed in the above reaction undergo reaction with $Br_2(CCl_4)$ individually,then the number of products formed will be:
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