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(A) The reaction of allylbenzene $(Ph-CH_2-CH=CH_2)$ with $HBr$ in the presence of peroxide follows the Anti-Markovnikov rule via a free radical mecha

Vedclass · Accepted Answer

$Ph-CH_2-CH_2-CH_2-Br$

Vedclass · Answer

(A) The reaction of allylbenzene $(Ph-CH_2-CH=CH_2)$ with $HBr$ in the presence of peroxide follows the Anti-Markovnikov rule via a free radical mechanism (Kharasch effect).In this mechanism,the bromine radical adds to the terminal carbon atom of the double bond to form a more stable radical intermediate.This intermediate then abstracts a hydrogen atom from $HBr$ to yield $Ph-CH_2-CH_2-CH_2-Br$ as the major product.

Write the major product of the following reaction: $Ph-CH_2-CH=CH_2 \xrightarrow{HBr, \text{Peroxide}}$

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